Mathematics Week 3 Graded Assignment

Mathematics Week 3 Graded Assignment


Graded Assignment

1. Consider three Airports A, B, and C. Two friends Ananya and Madhuri want to meet at Airport C. Ananya Boarded Flight 1 from Point A to C which is 1200 km, due to bad weather, Flight 1 slowed down, and the average speed was reduced by 200 km/h and the time increased by 30 minutes. Madhuri boarded Flight 2 from Point B to C which is 1800 km, the average speed of Flight 2 is 720 km/h. What is the waiting time, and who will be waiting at the airport? (Given Ananya and Madhuri boarded at the same time)

Waiting Time is 1 hr and Ananya is waiting.

Waiting Time is 1 hr and Madhuri is waiting.

Waiting Time is 30 min and Ananya is waiting.

Waiting Time is 30 min and Madhuri is waiting.

Step-by-Step Explanation:

  1. Determine Ananya’s Flight Details:
    • Let Ananya’s original speed be $ x $ km/h.
    • Original time: $ \frac{1200}{x} $ hours.
    • Reduced speed: $ x - 200 $ km/h.
    • New time: $ \frac{1200}{x - 200} $ hours.
    • Time increased by 30 minutes (0.5 hours):
$$ \frac{1200}{x - 200} - \frac{1200}{x} = 0.5 $$

2. Solve for $ x $:

  • Multiply through by $ x(x - 200) $:
$$ 1200x - 1200(x - 200) = 0.5x(x - 200) $$
  • Simplify:
$$ 240000 = 0.5x^2 - 100x \implies x^2 - 200x - 480000 = 0 $$
  • Solve the quadratic equation:
$$ x = \frac{200 \pm \sqrt{(200)^2 + 4 \cdot 480000}}{2} = \frac{200 \pm 1400}{2} $$
  • Valid solution: $ x = 800 $ km/h (original speed).
  1. Calculate Flight Times:
    • Ananya’s new time: $ \frac{1200}{800 - 200} = 2 $ hours.
    • Madhuri’s time: $ \frac{1800}{720} = 2.5 $ hours.
  2. Determine Waiting Time:
    • Ananya arrives in 2 hours, Madhuri in 2.5 hours.
    • Waiting time: $ 2.5 - 2 = 0.5 $ hours (30 minutes).
    • Who waits: Madhuri arrives later, so Ananya waits.

Final Answer:

\boxed{Waiting Time is 30 min and Ananya is waiting.}

Multiple Choice Questions (MSQ)

Question 1 If the slope of the parabola $y = a x^{2} + b x + c$ at $(2,3)$ is 5 and the $X$-coordinate of the vertex of the parabola is 3, then which of the following is/are true? Options:

(a) $y = -\frac{5}{2}x^{2} + 15x - 17$

(b) $y = \frac{5}{2}x^{2} + 15x - 17$

(c) $y = -\frac{5}{2}x^{2} + 15x + 17$

(d) $6y = -15x^{2} + 90x - 102$

Solution:

  • Option (a): Slope at $x=2$ is $-5(2)+15=5$. Vertex at $x=3$ (matches).
  • Option (b): Slope at $x=2$ is $5(2)+15=25$ (does not match).
  • Option (c): $y(2) = 27 \neq 3$ (does not pass through $(2,3)$).
  • Option (d): Equivalent to option (a). Correct options: (a), (d)

Question 2 Two parabolas $y = x^{2} + 3x + 2$ and $y = -x^{2} - 5x - 4$ are intersecting at two points $A$ (not on the $X$-axis) and $B$. Suppose a straight line $\ell_{1}$ passes through $A$ with slope equal to the slope of the parabola $y = -x^{2} - 5x - 4$ at point $A$ and two straight lines $\ell_{2}$ and $\ell_{3}$ pass through $B$ with slopes equal to the slopes of the parabolas $y = x^{2} + 3x + 2$ and $y = -x^{2} - 5x - 4$ at point $B$, respectively. Which of the following is/are true? Options:

(a) $\ell_{1}$ and $\ell_{2}$ are parallel.

(b) $\ell_{1}$ and $\ell_{3}$ are parallel.

(c) $\ell_{1}$ and $\ell_{3}$ are intersecting at point $(-2,3)$.

(d) $\ell_{2}$ and $\ell_{3}$ are intersecting at point $(-1,0)$.

Solution:

  • Intersection points: $(-3,2)$ and $(-1,0)$.
  • Slopes:
    • At $A(-3,2)$: slope of $y = -x^{2} - 5x - 4$ is $1$.
    • At $B(-1,0)$: slope of $y = x^{2} + 3x + 2$ is $1$; slope of $y = -x^{2} - 5x - 4$ is $-3$.
  • Equations:
    • $\ell_{1}$: $y = x + 5$
    • $\ell_{2}$: $y = x + 1$
    • $\ell_{3}$: $y = -3x - 3$
  • Analysis:
    • $\ell_{1}$ and $\ell_{2}$ are parallel (both have slope $1$).
    • $\ell_{1}$ and $\ell_{3}$ intersect at $(-2,3)$.
    • $\ell_{2}$ and $\ell_{3}$ intersect at $(-1,0)$. Correct options: (a), (c), (d)

Numerical Answer Type (NAT)

Question 3 Suppose $f(x) = a x^{2} + b x + c$, where $a, b, c \in \mathbb{Z} \setminus {0}$. The sum and product of roots of $f(x)$ are $\frac{-7}{4}$ and $\frac{-1}{2}$ respectively. Find the value of $2a + 4b + 2c$.

Solution:

  • Equation: $4x^{2} + 7x - 2 = 0$
  • Coefficients: $a=4$, $b=7$, $c=-2$
  • Calculation: $2a + 4b + 2c = 8 + 28 - 4 = 32$ Answer: $32$
Question 4 A class of 140 students are arranged in rows such that the number of students in a row is one less than thrice the number of rows. Find the number of students in each row.

Solution:

  • Let rows = $p$: $p(3p - 1) = 140$
  • Solve: $p=7$
  • Students per row: $3(7) - 1 = 20$ Answer: $20$

Comprehension Type Questions

The daily production cost (in lakh ₹) of manufacturing an electric device is $p(x) = 7400 - 60x + 15x^{2}$, where $x$ is the number of electric devices produced per day. The daily transportation cost (in lakh ₹) of $x$ devices is given by the slope of $p(x)$ at point $x$.

Question 5 How many electric devices should be produced per day to yield minimum production cost?

Solution:

  • Minimum at $x = 2$ Answer: $2$
Question 6 If the transportation cost on a day is 30 (in lakh ₹), find the number of devices transported.

Solution:

  • Slope: $30x - 60 = 30 \implies x = 3$ Answer: $3$
Question 7 If the production cost on a day is 7475 (in lakh ₹), find the number of devices produced.

Solution:

  • Solve: $x=5$ (only positive solution) Answer: $5$
Question 8 If the slope of parabola $y = a x^{2} + b x + c$ at points $(3,2)$ and $(2,3)$ are 16 and 12 respectively, find $a$.

Solution:

  • Solve: $6a + b = 16$, $4a + b = 12$
  • Subtract: $2a = 4 \implies a = 2$ Answer: $2$
Question 9 The product of two consecutive odd natural numbers is 143. Find the largest number among them.

Solution:

  • Numbers: $11, 13$ Answer: $13$
Question 10 The slope of a parabola $y = 3x^{2} - 11x + 10$ at a point $P$ is 7. Find the $y$-coordinate of $P$.

Solution:

  • Slope: $6x - 11 = 7 \implies x = 3$
  • $y(3) = 4$ Answer: $4$

Additional Questions (from later sections of the PDF)

Question 11 Find out the points where the curve $y = 4x^{2} + x$ and the straight line $y = 2x - 3$ intersect with each other. Solution:

  • No real intersection points. Answer: The curve and the straight line do not intersect.

Question 12 Let $a$ and $b$ be two consecutive positive odd natural numbers such that $a^{2} + b^{2} = 394$. Find the value of $a + b$. Solution:

  • Numbers: $13, 15$
  • Sum: $28$ Answer: $28$

Question 13 A class of 352 students are arranged in rows such that the number of students in a row is one less than thrice the number of rows. Find the number of students in each row. Solution:

  • Let rows = $x$: $x(3x - 1) = 352$
  • Solve: $x=11$
  • Students per row: $3(11) - 1 = 32$ Answer: $32$

Question 14 In order to cover a fixed distance of 48 km, two vehicles start from the same place. The faster one takes 2 hrs less and has a speed 4 km/hr more than the slower one. (a) What is the speed (in km/hr) of the slower vehicle? Solution:

  • Speed: $x = 8$ km/hr Answer: $8$

(b) What is the time (in hrs) taken by the faster one? Solution:

  • Time: $48 / 12 = 4$ hrs Answer: $4$

Question 15 The maximum value of a quadratic function $f$ is $-3$, its axis of symmetry is $x=2$, and the value at $x=0$ is $-9$. What will be the coefficient of $x^{2}$ in the expression of $f$? Solution:

  • Coefficient: $-1.5$ Answer: $-1.5$

Question 16 A ball is thrown from 3 m off the ground and reaches a maximum height of 5 m. It returns to 3 m after 2 seconds. Let $h(t) = a t^{2} + b t + c$ be the height function. What is the value of $a$? Solution:

  • Using points: $(0,3)$, $(1,5)$, $(2,3)$
  • Solve: $a = -2$ Answer: $-2$

Question 17 The product of two consecutive odd natural numbers is 255. Find the largest number among them. Solution:

  • Numbers: $15, 17$ Answer: $17$

Question 18 The slope of a parabola $y = 3x^{2} - 11x + 10$ at a point $P$ is 1. Find the $y$-coordinate of $P$. Solution:

  • Slope: $6x - 11 = 1 \implies x = 2$
  • $y(2) = 0$ Answer: $0$

Question 19 A ball is thrown. The height function is $h(t) = -0.5 t^{2} + 4 t + 1$. What is the time taken to reach maximum height? Solution:

  • Time: $t = 4$ Answer: $4$

Question 20 What is the maximum height attained? Solution:

  • Height: $h(4) = 9$ Answer: $9$

Summary Table

QDescriptionSolution/Answer
1Parabola slope/vertex(a), (d)
2Parabola intersections, lines(a), (c), (d)
3Quadratic roots, sum/product32
4Students in rows20
5Minimum production cost2
6Transportation cost3
7Production cost5
8Parabola slope at points2
9Product of odd numbers13
10Parabola slope, y-coord4
11Curve-line intersectionNo intersection
12Sum of consecutive odds28
13Students in rows (352)32
14aSlower vehicle speed8 km/hr
14bFaster vehicle time4 hrs
15Quadratic coefficient-1.5
16Ball height, a value-2
17Product of odd numbers (255)17
18Parabola slope, y-coord0
19Ball max height time4
20Ball max height9

This covers all questions and solutions from the Week-3.pdf file1.


  1. Week-3.pdf ↩︎