Mathematics Week 3 Graded Assignment
Graded Assignment
1. Consider three Airports A, B, and C. Two friends Ananya and Madhuri want to meet at Airport C. Ananya Boarded Flight 1 from Point A to C which is 1200 km, due to bad weather, Flight 1 slowed down, and the average speed was reduced by 200 km/h and the time increased by 30 minutes. Madhuri boarded Flight 2 from Point B to C which is 1800 km, the average speed of Flight 2 is 720 km/h. What is the waiting time, and who will be waiting at the airport? (Given Ananya and Madhuri boarded at the same time)
Waiting Time is 1 hr and Ananya is waiting.
Waiting Time is 1 hr and Madhuri is waiting.
Waiting Time is 30 min and Ananya is waiting.
Waiting Time is 30 min and Madhuri is waiting.
Step-by-Step Explanation:
- Determine Ananya’s Flight Details:
- Let Ananya’s original speed be $ x $ km/h.
- Original time: $ \frac{1200}{x} $ hours.
- Reduced speed: $ x - 200 $ km/h.
- New time: $ \frac{1200}{x - 200} $ hours.
- Time increased by 30 minutes (0.5 hours):
2. Solve for $ x $:
- Multiply through by $ x(x - 200) $:
- Simplify:
- Solve the quadratic equation:
- Valid solution: $ x = 800 $ km/h (original speed).
- Calculate Flight Times:
- Ananya’s new time: $ \frac{1200}{800 - 200} = 2 $ hours.
- Madhuri’s time: $ \frac{1800}{720} = 2.5 $ hours.
- Determine Waiting Time:
- Ananya arrives in 2 hours, Madhuri in 2.5 hours.
- Waiting time: $ 2.5 - 2 = 0.5 $ hours (30 minutes).
- Who waits: Madhuri arrives later, so Ananya waits.
Final Answer:
\boxed{Waiting Time is 30 min and Ananya is waiting.}
Multiple Choice Questions (MSQ)
Question 1 If the slope of the parabola $y = a x^{2} + b x + c$ at $(2,3)$ is 5 and the $X$-coordinate of the vertex of the parabola is 3, then which of the following is/are true? Options:
(a) $y = -\frac{5}{2}x^{2} + 15x - 17$
(b) $y = \frac{5}{2}x^{2} + 15x - 17$
(c) $y = -\frac{5}{2}x^{2} + 15x + 17$
(d) $6y = -15x^{2} + 90x - 102$
Solution:
- Option (a): Slope at $x=2$ is $-5(2)+15=5$. Vertex at $x=3$ (matches).
- Option (b): Slope at $x=2$ is $5(2)+15=25$ (does not match).
- Option (c): $y(2) = 27 \neq 3$ (does not pass through $(2,3)$).
- Option (d): Equivalent to option (a). Correct options: (a), (d)
Question 2 Two parabolas $y = x^{2} + 3x + 2$ and $y = -x^{2} - 5x - 4$ are intersecting at two points $A$ (not on the $X$-axis) and $B$. Suppose a straight line $\ell_{1}$ passes through $A$ with slope equal to the slope of the parabola $y = -x^{2} - 5x - 4$ at point $A$ and two straight lines $\ell_{2}$ and $\ell_{3}$ pass through $B$ with slopes equal to the slopes of the parabolas $y = x^{2} + 3x + 2$ and $y = -x^{2} - 5x - 4$ at point $B$, respectively. Which of the following is/are true? Options:
(a) $\ell_{1}$ and $\ell_{2}$ are parallel.
(b) $\ell_{1}$ and $\ell_{3}$ are parallel.
(c) $\ell_{1}$ and $\ell_{3}$ are intersecting at point $(-2,3)$.
(d) $\ell_{2}$ and $\ell_{3}$ are intersecting at point $(-1,0)$.
Solution:
- Intersection points: $(-3,2)$ and $(-1,0)$.
- Slopes:
- At $A(-3,2)$: slope of $y = -x^{2} - 5x - 4$ is $1$.
- At $B(-1,0)$: slope of $y = x^{2} + 3x + 2$ is $1$; slope of $y = -x^{2} - 5x - 4$ is $-3$.
- Equations:
- $\ell_{1}$: $y = x + 5$
- $\ell_{2}$: $y = x + 1$
- $\ell_{3}$: $y = -3x - 3$
- Analysis:
- $\ell_{1}$ and $\ell_{2}$ are parallel (both have slope $1$).
- $\ell_{1}$ and $\ell_{3}$ intersect at $(-2,3)$.
- $\ell_{2}$ and $\ell_{3}$ intersect at $(-1,0)$. Correct options: (a), (c), (d)
Numerical Answer Type (NAT)
Solution:
- Equation: $4x^{2} + 7x - 2 = 0$
- Coefficients: $a=4$, $b=7$, $c=-2$
- Calculation: $2a + 4b + 2c = 8 + 28 - 4 = 32$ Answer: $32$
Solution:
- Let rows = $p$: $p(3p - 1) = 140$
- Solve: $p=7$
- Students per row: $3(7) - 1 = 20$ Answer: $20$
Comprehension Type Questions
The daily production cost (in lakh ₹) of manufacturing an electric device is $p(x) = 7400 - 60x + 15x^{2}$, where $x$ is the number of electric devices produced per day. The daily transportation cost (in lakh ₹) of $x$ devices is given by the slope of $p(x)$ at point $x$.
Solution:
- Minimum at $x = 2$ Answer: $2$
Solution:
- Slope: $30x - 60 = 30 \implies x = 3$ Answer: $3$
Solution:
- Solve: $x=5$ (only positive solution) Answer: $5$
Solution:
- Solve: $6a + b = 16$, $4a + b = 12$
- Subtract: $2a = 4 \implies a = 2$ Answer: $2$
Solution:
- Numbers: $11, 13$ Answer: $13$
Solution:
- Slope: $6x - 11 = 7 \implies x = 3$
- $y(3) = 4$ Answer: $4$
Additional Questions (from later sections of the PDF)
Question 11 Find out the points where the curve $y = 4x^{2} + x$ and the straight line $y = 2x - 3$ intersect with each other. Solution:
- No real intersection points. Answer: The curve and the straight line do not intersect.
Question 12 Let $a$ and $b$ be two consecutive positive odd natural numbers such that $a^{2} + b^{2} = 394$. Find the value of $a + b$. Solution:
- Numbers: $13, 15$
- Sum: $28$ Answer: $28$
Question 13 A class of 352 students are arranged in rows such that the number of students in a row is one less than thrice the number of rows. Find the number of students in each row. Solution:
- Let rows = $x$: $x(3x - 1) = 352$
- Solve: $x=11$
- Students per row: $3(11) - 1 = 32$ Answer: $32$
Question 14 In order to cover a fixed distance of 48 km, two vehicles start from the same place. The faster one takes 2 hrs less and has a speed 4 km/hr more than the slower one. (a) What is the speed (in km/hr) of the slower vehicle? Solution:
- Speed: $x = 8$ km/hr Answer: $8$
(b) What is the time (in hrs) taken by the faster one? Solution:
- Time: $48 / 12 = 4$ hrs Answer: $4$
Question 15 The maximum value of a quadratic function $f$ is $-3$, its axis of symmetry is $x=2$, and the value at $x=0$ is $-9$. What will be the coefficient of $x^{2}$ in the expression of $f$? Solution:
- Coefficient: $-1.5$ Answer: $-1.5$
Question 16 A ball is thrown from 3 m off the ground and reaches a maximum height of 5 m. It returns to 3 m after 2 seconds. Let $h(t) = a t^{2} + b t + c$ be the height function. What is the value of $a$? Solution:
- Using points: $(0,3)$, $(1,5)$, $(2,3)$
- Solve: $a = -2$ Answer: $-2$
Question 17 The product of two consecutive odd natural numbers is 255. Find the largest number among them. Solution:
- Numbers: $15, 17$ Answer: $17$
Question 18 The slope of a parabola $y = 3x^{2} - 11x + 10$ at a point $P$ is 1. Find the $y$-coordinate of $P$. Solution:
- Slope: $6x - 11 = 1 \implies x = 2$
- $y(2) = 0$ Answer: $0$
Question 19 A ball is thrown. The height function is $h(t) = -0.5 t^{2} + 4 t + 1$. What is the time taken to reach maximum height? Solution:
- Time: $t = 4$ Answer: $4$
Question 20 What is the maximum height attained? Solution:
- Height: $h(4) = 9$ Answer: $9$
Summary Table
Q | Description | Solution/Answer |
---|---|---|
1 | Parabola slope/vertex | (a), (d) |
2 | Parabola intersections, lines | (a), (c), (d) |
3 | Quadratic roots, sum/product | 32 |
4 | Students in rows | 20 |
5 | Minimum production cost | 2 |
6 | Transportation cost | 3 |
7 | Production cost | 5 |
8 | Parabola slope at points | 2 |
9 | Product of odd numbers | 13 |
10 | Parabola slope, y-coord | 4 |
11 | Curve-line intersection | No intersection |
12 | Sum of consecutive odds | 28 |
13 | Students in rows (352) | 32 |
14a | Slower vehicle speed | 8 km/hr |
14b | Faster vehicle time | 4 hrs |
15 | Quadratic coefficient | -1.5 |
16 | Ball height, a value | -2 |
17 | Product of odd numbers (255) | 17 |
18 | Parabola slope, y-coord | 0 |
19 | Ball max height time | 4 |
20 | Ball max height | 9 |
This covers all questions and solutions from the Week-3.pdf file1.
Week-3.pdf ↩︎