is_odd_length_palindrome

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🔄 Sum and Absolute Difference Alternately Let’s solve the problem step by step and make the code easy-to-follow with emojis, practice questions, and explanations! 🚀 📝 Full Python Code n = int(input()) for i in range(n): line = input().strip() # Split by comma and convert to integers a, b = map(int, line.split(',')) if i % 2 == 0: # Odd-numbered pair (1-based): print sum print(a + b) else: # Even-numbered pair (1-based): print absolute difference print(abs(a - b)) 🔍 Step-by-Step Explanation Read the number of pairs: The first input line is the integer n. Process each pair: For every line, read two comma-separated integers. Odd pair (1st, 3rd, 5th…): Print their sum. Even pair (2nd, 4th, 6th…): Print the absolute difference. Print the results one per line. 🧪 Practice Questions (with Solutions!) Practice 1 Input:

Check if a Number is Divisible by Exactly One of the Given NumbersWrite a function div_by_exactly_one that takes three integers num, a, and b. The function should return True if num is divisible by exactly one of the numbers a or b, and False otherwise. NOTE: This is a function type question, you don’t have to take input or print the output, just have to complete the required function definition.

📝 Filter Words by Custom Criteria Below is the requested function to filter a list of words based on one of four criteria: continuous, vowel_rich, consonant_rich, or sorted. Words are checked case-insensitively, and helper functions are included for each criteria. def filter_words(words, criteria): """ Filters a list of words based on the given criteria. Args: words (list of str): Input list of words. criteria (str): One of 'continuous', 'vowel_rich', 'consonant_rich', 'sorted'. Returns: list or None: Filtered list based on criteria, or None if invalid. Criteria: • 'continuous': words ending with 'ing' (case-insensitive) • 'vowel_rich': words with more than 5 vowels • 'consonant_rich': words with more than 5 consonants • 'sorted': words whose letters are in ascending order (case-insensitive) """ def is_continuous(word): return word.lower().endswith('ing') def count_vowels(word): return sum(1 for ch in word.lower() if ch in "aeiou") def count_consonants(word): return sum(1 for ch in word.lower() if ch.isalpha() and ch not in "aeiou") def is_sorted(word): letters = [ch.lower() for ch in word if ch.isalpha()] return letters == sorted(letters) if criteria == 'continuous': return [w for w in words if is_continuous(w)] elif criteria == 'vowel_rich': return [w for w in words if count_vowels(w) > 5] elif criteria == 'consonant_rich': return [w for w in words if count_consonants(w) > 5] elif criteria == 'sorted': return [w for w in words if is_sorted(w)] else: return None ✨ Step-by-Step Explanation Helper Functions: is_continuous: Checks if the word ends with “ing” (case-insensitive). count_vowels: Counts vowels (a, e, i, o, u). count_consonants: Counts consonants (alphabetic letters that are not vowels). is_sorted: Checks if the letters of the word are in ascending order. Criteria Check: The function checks the criteria argument and applies the relevant helper. If an unknown criteria is given, returns None. 🧪 Practice Questions Try calling the function on the following list:

🔎 Function: Find Last Word Starting with Uppercase Here’s how you can implement the last_word_starts_with_upper_case function to find the last word in a sentence that starts with an uppercase letter. If no such word exists, it returns None. 🛠️ Function Definition def last_word_starts_with_upper_case(sentence: str): """ Find the last word in a sentence that starts with an uppercase letter. Args: sentence (str): The input sentence. Returns: str or None: The last word starting with an uppercase letter, or None if no such word exists. """ result = None for word in sentence.split(): if word and word[0].isupper(): result = word return result ✨ Step-by-Step Explanation Step 1: Split the sentence into individual words using split(). Step 2: Loop through each word: If the word starts with an uppercase letter (word.isupper()), save it as the current result. Step 3: After checking all words, return the last word found that met the criteria, or None if none did. 🚦 Example Usage print(last_word_starts_with_upper_case("This is a Test sentence")) # Output: "Test" print(last_word_starts_with_upper_case("no uppercase words here")) # Output: None 📝 Practice Questions What will last_word_starts_with_upper_case("Alice and Bob went to Paris") return? Try last_word_starts_with_upper_case("all lowercase words"). What is the result of last_word_starts_with_upper_case("Python Is Easy To Learn")? ✅ Solutions "Paris" None "Learn" With this function, you can quickly scan sentences for the last word that begins with a capital letter. Perfect for text analysis and simple parsing tasks! 🐍💡

🔢 Function: Count Positive Integers (Ignore None) Let’s build an easy-to-use Python function! ✨ 🚩 Function Definition def count_positive_integers(lst): return sum(1 for x in lst if x is not None and isinstance(x, int) and x > 0) 📝 Step-by-Step Explanation Iterate through each element x in the list. Ignore None values (x is not None). Check if the value is an integer (isinstance(x, int)). Count only if the integer is positive (x > 0, so zero is ignored). Sum up the count (sum(1 for ...)). 🧪 Practice Questions Practice 1 lst = [4, -3, None, 7, 0, None, 10] print(count_positive_integers(lst)) # _______ Answer: 3 (Counts 4, 7, 10)

📝 Function: within_and_has_double_quotes Let’s build a Python function to check if a string: Starts and ends with double quotes (") Has at least one double quote somewhere inside (not including the first and last characters) 🧑‍💻 Function Implementation def within_and_has_double_quotes(s): # Check if string has at least 2 characters and starts/ends with a double quote if len(s) < 2 or s[0] != '"' or s[-1] != '"': return False # Check for another double quote in the interior (exclude first/last char) return '"' in s[1:-1] 🔍 Step-by-Step Explanation Check the boundary quotes: The string must be at least 2 characters. The first character is " and the last character is ". Check for an internal quote: Use s[1:-1] to get the inner part of the string (excluding first and last characters). Test if " exists in this interior slice. 🧪 Practice Questions Practice 1 print(within_and_has_double_quotes('"hello"')) # _______ Interior: hello (no quotes) Output: False Practice 2 print(within_and_has_double_quotes('"he"llo"')) # _______ Interior: he"llo Yes, has an interior double quote! Output: True Practice 3 print(within_and_has_double_quotes('""')) # _______ Interior: empty string "" Output: False Practice 4 print(within_and_has_double_quotes('"a"b"c"')) # _______ Interior: a"b"c Yes, contains double quotes inside! Output: True Practice 5 print(within_and_has_double_quotes('"no inner quote')) # _______ No ending double quote. Output: False ✅ Key Points Checks boundaries (" at both ends) Looks inside (middle of string) for at least one more double quote Returns True only if both conditions are met Happy Coding! 🚀