Let’s break down the task and provide a clear solution!
🚩 What should the function do?
Remove two elements from a list, given their indices.
The function modifies the list in place (does not return anything).
Indices are unique and non-negative.
🧑💻 Function Implementation
defremove_elements_at_two_indices(l,i1,i2):# Sort indices in reverse order to avoid messing up positions after deletionforidxinsorted([i1,i2],reverse=True):dell[idx]
🔍 Step-by-Step Explanation
Why reverse order?
Removing elements by index shifts subsequent items left.
By deleting the bigger index first, the smaller index’s position is unaffected.
How it works:
sorted([i1, i2], reverse=True) sorts indices from largest to smallest.
del l[idx] removes the element at index idx.
🧪 Practice: Try It Yourself!
Practice 1
lst=[10,20,30,40,50]remove_elements_at_two_indices(lst,1,3)print(lst)# What is the result?
Practice 2
lst=['a','b','c','d','e','f']remove_elements_at_two_indices(lst,0,4)print(lst)# What is the result?
Practice 3
lst=[1,2,3]remove_elements_at_two_indices(lst,1,2)print(lst)# What is the result?
✅ Solutions
# Practice 1# Remove at indices 1 and 3: [10, 20, 30, 40, 50] -> [10, 30, 40, 50] -> [10, 30, 50]# Answer: [10, 30, 50]# Practice 2# Remove indices 0 and 4: ['a', 'b', 'c', 'd', 'e', 'f'] -> ['b', 'c', 'd', 'e', 'f'] -> ['b', 'c', 'd', 'f']# Answer: ['b', 'c', 'd', 'f']# Practice 3# Remove indices 1 and 2: [1, 2, 3] -> [1, 2] (after removing 2nd) -> [1] (after removing 1st)# Answer: [1]
✨ Points to Remember
In-place change: The original list is modified!
Reverse order deletion: Always delete from the highest index first to avoid shifting problems.
No return value: The function only changes the input list.
