Program - Vowels Uppercase, Others Lowercase

Let's solve your problem step by step!

✨ Print “X” Pattern Program Let’s write a Python program that prints an “X” shaped pattern using backslashes (\), forward slashes (/), and a lowercase x in the center! 😃 📋 Problem Description Input: An integer n (n >= 0) Output: An “X” shape with a center "x" and n identical rows above and below, built with slashes. No extra spaces to the right of the pattern. 🧑‍💻 Full Python Code n = int(input()) # Print the top part for i in range(n): # i spaces, then '\', then (2*n - 2*i - 1) spaces, then '/' left_spaces = ' ' * i middle_spaces = ' ' * (2 * n - 2 * i - 1) print(left_spaces + '\\' + middle_spaces + '/') # Print the central x print(' ' * n + 'x') # Print the bottom part (mirror of above) for i in range(n-1, -1, -1): left_spaces = ' ' * i middle_spaces = ' ' * (2 * n - 2 * i - 1) print(left_spaces + '/' + middle_spaces + '\\') 🔍 Step-by-Step Explanation Top Rows: For each row i from 0 to n-1: Print i spaces. Print a backslash (\). Print (2*n - 2*i - 1) spaces (between slashes). Print a forward slash (/). Central Row: Print n spaces, then the character 'x'. Bottom Rows: Repeat in reverse for i from n-1 to 0: Print i spaces. Print a forward slash (/). Print (2*n - 2*i - 1) spaces. Print a backslash (\). No trailing spaces are added to the right of the pattern. 🧪 Practice Examples Example 1 Input:

🔄 Sum and Absolute Difference Alternately Let’s solve the problem step by step and make the code easy-to-follow with emojis, practice questions, and explanations! 🚀 📝 Full Python Code n = int(input()) for i in range(n): line = input().strip() # Split by comma and convert to integers a, b = map(int, line.split(',')) if i % 2 == 0: # Odd-numbered pair (1-based): print sum print(a + b) else: # Even-numbered pair (1-based): print absolute difference print(abs(a - b)) 🔍 Step-by-Step Explanation Read the number of pairs: The first input line is the integer n. Process each pair: For every line, read two comma-separated integers. Odd pair (1st, 3rd, 5th…): Print their sum. Even pair (2nd, 4th, 6th…): Print the absolute difference. Print the results one per line. 🧪 Practice Questions (with Solutions!) Practice 1 Input:

🚀 Function: increment_value_with_max_limit Here’s a function to increment the value for a given key in a dictionary, making sure it never exceeds a specified maximum limit! def increment_value_with_max_limit(d, key, inc, limit): """ Increment the value of d[key] by inc, but do not let it exceed limit. Args: d (dict): Dictionary with integer values. key: Key whose value you want to increment. inc (int): The increment value. limit (int): The maximum allowed value. Returns: None: The dictionary is modified in-place. Example: d = {'a': 5} increment_value_with_max_limit(d, 'a', 10, 12) # Now d['a'] == 12 """ if key in d: d[key] = min(d[key] + inc, limit) ✨ Step-by-Step Explanation Check Key Exists: Make sure the key is present in the dictionary. Increment and Cap: Add the inc value to the current value for the key. Use min(new_value, limit) to cap the result at limit if it would go over. Update In Place: The original dictionary is modified directly. No return value necessary! 📝 Practice Questions If d = {'x': 7}, what does increment_value_with_max_limit(d, 'x', 4, 10) do? What happens for d = {'b': 2}, increment_value_with_max_limit(d, 'b', 5, 5)? Try d = {'score': 20}, increment_value_with_max_limit(d, 'score', 3, 22) ✅ Solutions The value becomes min(7+4, 10) = 10. So, d['x'] will be 10. The value becomes min(2+5, 5) = 5. So, d['b'] will be 5. The value becomes min(20+3, 22) = 22. So, d['score'] will be 22. 💡 Now you can safely increment dictionary values without ever exceeding the maximum you set!

def print_n_pattern(n): """ Prints an "N" shaped pattern with n rows. The pattern has vertical bars (|) on the left and right sides of each row, with a backslash (\) moving diagonally from the top-left to the bottom-right. There are no spaces to the right of the pattern. Args: n (int): The number of rows for the pattern (n > 0). """ for i in range(n): # Start each row with a vertical bar row = "|" # Add leading spaces before the diagonal backslash # The number of leading spaces is equal to the current row index 'i' row += " " * i # Add the diagonal backslash row += "\\" # Add trailing spaces after the diagonal backslash # The total width of the inner part (between vertical bars) is (n - 1) characters. # So, the number of trailing spaces is (n - 1) - i row += " " * (n - 1 - i) # End each row with a vertical bar row += "|" # Print the constructed row print(row) if __name__ == "__main__": try: # Read the integer input from the user n = int(input()) # Validate the input: n must be greater than 0 if n <= 0: print("Input 'n' must be a positive integer (n > 0).") else: # Call the function to print the pattern print_n_pattern(n) except ValueError: # Handle cases where the input is not a valid integer print("Invalid input. Please enter a single integer.")

Check if a Number is Divisible by Exactly One of the Given NumbersWrite a function div_by_exactly_one that takes three integers num, a, and b. The function should return True if num is divisible by exactly one of the numbers a or b, and False otherwise. NOTE: This is a function type question, you don’t have to take input or print the output, just have to complete the required function definition.

🏃‍♂️ Matrix Walk Function Let’s design a Python function that follows three special matrix paths — “L”, “Z”, and “O” shapes — and collects the matrix elements accordingly! 🚀 🧑‍💻 Function Definition def matrix_walk(matrix, path): n = len(matrix) result = [] if path == "L": # Down the first column for i in range(n): result.append(matrix[i][0]) # Across the bottom row, excluding first element for j in range(1, n): result.append(matrix[n-1][j]) return result elif path == "Z": # Top row for j in range(n): result.append(matrix[0][j]) # Diagonal except first and last row for i in range(1, n-1): result.append(matrix[i][n-i-1]) # Bottom row for j in range(n): result.append(matrix[n-1][j]) return result elif path == "O": # Top row for j in range(n): result.append(matrix[0][j]) # Right column (excluding top and bottom) for i in range(1, n-1): result.append(matrix[i][n-1]) # Bottom row (reverse, excluding last element) for j in range(n-1, -1, -1): result.append(matrix[n-1][j]) # Left column (reverse, excluding top and bottom) for i in range(n-2, 0, -1): result.append(matrix[i][0]) return result else: return [] 🔍 Step-by-Step Explanation 1. L-Shape (“L”) Walk down the first column (leftmost). Then walk right along the bottom row (skipping the already-added first element). 2. Z-Shape (“Z”) Walk across the top row (left to right). Walk diagonally from the top-right to bottom-left, excluding corners. Walk across the bottom row (left to right). 3. O-Shape (“O”) Walk around the outside (clockwise): Top row (left to right), Right column (top to bottom, skipping corners), Bottom row (right to left), Left column (bottom to top, skipping corners). 🧪 Practice Questions with Solutions Example Matrix matrix = [ [1, 2, 3], [4, 5, 6], [7, 8, 9] ] Practice 1: L-Shape print(matrix_walk(matrix, "L")) # Output: [1, 4, 7, 8, 9] Practice 2: Z-Shape print(matrix_walk(matrix, "Z")) # Output: [1, 2, 3, 5, 7, 8, 9] Practice 3: O-Shape print(matrix_walk(matrix, "O")) # Output: [1, 2, 3, 6, 9, 8, 7, 4] ✨ Key Points The function traverses only as per the specified path — “L”, “Z”, or “O”. For unknown paths, returns an empty list. Works for any square matrix of size 1 or more. Happy Matrix Walking! 🟦🟩🟨🟥

🔢 Function: Count Positive Integers (Ignore None) Let’s build an easy-to-use Python function! ✨ 🚩 Function Definition def count_positive_integers(lst): return sum(1 for x in lst if x is not None and isinstance(x, int) and x > 0) 📝 Step-by-Step Explanation Iterate through each element x in the list. Ignore None values (x is not None). Check if the value is an integer (isinstance(x, int)). Count only if the integer is positive (x > 0, so zero is ignored). Sum up the count (sum(1 for ...)). 🧪 Practice Questions Practice 1 lst = [4, -3, None, 7, 0, None, 10] print(count_positive_integers(lst)) # _______ Answer: 3 (Counts 4, 7, 10)