V Shaped Pattern Printer

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🔄 Swap and Reverse Lines Program in Python Below is a Python program that reads multiple lines of input, swaps every two consecutive lines, and then reverses every odd-numbered line in the resulting output sequence. This meets the problem’s requirements exactly. 🛠️ Complete Code def main(): n = int(input()) lines = [input() for _ in range(n)] # Swap every two consecutive lines for i in range(0, n - 1, 2): lines[i], lines[i + 1] = lines[i + 1], lines[i] # Reverse every odd-numbered line in the output (1-based index) for i in range(n): if (i + 1) % 2 == 1: # odd line number lines[i] = lines[i][::-1] # Print the transformed lines for line in lines: print(line) if __name__ == "__main__": main() 📝 Explanation Input Reading: Read the integer n for the number of lines, then read each line into a list. Swapping Consecutive Lines: Iterate through the list in steps of two, swapping the pair at indices i and i+1. Reversing Odd-Numbered Lines: After swapping, reverse every odd line (1st, 3rd, 5th, …) by checking (i+1) % 2 == 1. Output: Print each line after these transformations. 🌟 Example Run Input:

✨ Print “X” Pattern Program Let’s write a Python program that prints an “X” shaped pattern using backslashes (\), forward slashes (/), and a lowercase x in the center! 😃 📋 Problem Description Input: An integer n (n >= 0) Output: An “X” shape with a center "x" and n identical rows above and below, built with slashes. No extra spaces to the right of the pattern. 🧑‍💻 Full Python Code n = int(input()) # Print the top part for i in range(n): # i spaces, then '\', then (2*n - 2*i - 1) spaces, then '/' left_spaces = ' ' * i middle_spaces = ' ' * (2 * n - 2 * i - 1) print(left_spaces + '\\' + middle_spaces + '/') # Print the central x print(' ' * n + 'x') # Print the bottom part (mirror of above) for i in range(n-1, -1, -1): left_spaces = ' ' * i middle_spaces = ' ' * (2 * n - 2 * i - 1) print(left_spaces + '/' + middle_spaces + '\\') 🔍 Step-by-Step Explanation Top Rows: For each row i from 0 to n-1: Print i spaces. Print a backslash (\). Print (2*n - 2*i - 1) spaces (between slashes). Print a forward slash (/). Central Row: Print n spaces, then the character 'x'. Bottom Rows: Repeat in reverse for i from n-1 to 0: Print i spaces. Print a forward slash (/). Print (2*n - 2*i - 1) spaces. Print a backslash (\). No trailing spaces are added to the right of the pattern. 🧪 Practice Examples Example 1 Input:

📝 Function: within_and_has_double_quotes Let’s build a Python function to check if a string: Starts and ends with double quotes (") Has at least one double quote somewhere inside (not including the first and last characters) 🧑‍💻 Function Implementation def within_and_has_double_quotes(s): # Check if string has at least 2 characters and starts/ends with a double quote if len(s) < 2 or s[0] != '"' or s[-1] != '"': return False # Check for another double quote in the interior (exclude first/last char) return '"' in s[1:-1] 🔍 Step-by-Step Explanation Check the boundary quotes: The string must be at least 2 characters. The first character is " and the last character is ". Check for an internal quote: Use s[1:-1] to get the inner part of the string (excluding first and last characters). Test if " exists in this interior slice. 🧪 Practice Questions Practice 1 print(within_and_has_double_quotes('"hello"')) # _______ Interior: hello (no quotes) Output: False Practice 2 print(within_and_has_double_quotes('"he"llo"')) # _______ Interior: he"llo Yes, has an interior double quote! Output: True Practice 3 print(within_and_has_double_quotes('""')) # _______ Interior: empty string "" Output: False Practice 4 print(within_and_has_double_quotes('"a"b"c"')) # _______ Interior: a"b"c Yes, contains double quotes inside! Output: True Practice 5 print(within_and_has_double_quotes('"no inner quote')) # _______ No ending double quote. Output: False ✅ Key Points Checks boundaries (" at both ends) Looks inside (middle of string) for at least one more double quote Returns True only if both conditions are met Happy Coding! 🚀

🏃‍♂️ Matrix Walk Function Let’s design a Python function that follows three special matrix paths — “L”, “Z”, and “O” shapes — and collects the matrix elements accordingly! 🚀 🧑‍💻 Function Definition def matrix_walk(matrix, path): n = len(matrix) result = [] if path == "L": # Down the first column for i in range(n): result.append(matrix[i][0]) # Across the bottom row, excluding first element for j in range(1, n): result.append(matrix[n-1][j]) return result elif path == "Z": # Top row for j in range(n): result.append(matrix[0][j]) # Diagonal except first and last row for i in range(1, n-1): result.append(matrix[i][n-i-1]) # Bottom row for j in range(n): result.append(matrix[n-1][j]) return result elif path == "O": # Top row for j in range(n): result.append(matrix[0][j]) # Right column (excluding top and bottom) for i in range(1, n-1): result.append(matrix[i][n-1]) # Bottom row (reverse, excluding last element) for j in range(n-1, -1, -1): result.append(matrix[n-1][j]) # Left column (reverse, excluding top and bottom) for i in range(n-2, 0, -1): result.append(matrix[i][0]) return result else: return [] 🔍 Step-by-Step Explanation 1. L-Shape (“L”) Walk down the first column (leftmost). Then walk right along the bottom row (skipping the already-added first element). 2. Z-Shape (“Z”) Walk across the top row (left to right). Walk diagonally from the top-right to bottom-left, excluding corners. Walk across the bottom row (left to right). 3. O-Shape (“O”) Walk around the outside (clockwise): Top row (left to right), Right column (top to bottom, skipping corners), Bottom row (right to left), Left column (bottom to top, skipping corners). 🧪 Practice Questions with Solutions Example Matrix matrix = [ [1, 2, 3], [4, 5, 6], [7, 8, 9] ] Practice 1: L-Shape print(matrix_walk(matrix, "L")) # Output: [1, 4, 7, 8, 9] Practice 2: Z-Shape print(matrix_walk(matrix, "Z")) # Output: [1, 2, 3, 5, 7, 8, 9] Practice 3: O-Shape print(matrix_walk(matrix, "O")) # Output: [1, 2, 3, 6, 9, 8, 7, 4] ✨ Key Points The function traverses only as per the specified path — “L”, “Z”, or “O”. For unknown paths, returns an empty list. Works for any square matrix of size 1 or more. Happy Matrix Walking! 🟦🟩🟨🟥

Check if a Number is Divisible by Exactly One of the Given NumbersWrite a function div_by_exactly_one that takes three integers num, a, and b. The function should return True if num is divisible by exactly one of the numbers a or b, and False otherwise. NOTE: This is a function type question, you don’t have to take input or print the output, just have to complete the required function definition.

🔢 Function: Count Positive Integers (Ignore None) Let’s build an easy-to-use Python function! ✨ 🚩 Function Definition def count_positive_integers(lst): return sum(1 for x in lst if x is not None and isinstance(x, int) and x > 0) 📝 Step-by-Step Explanation Iterate through each element x in the list. Ignore None values (x is not None). Check if the value is an integer (isinstance(x, int)). Count only if the integer is positive (x > 0, so zero is ignored). Sum up the count (sum(1 for ...)). 🧪 Practice Questions Practice 1 lst = [4, -3, None, 7, 0, None, 10] print(count_positive_integers(lst)) # _______ Answer: 3 (Counts 4, 7, 10)