Here’s a function to increment the value for a given key in a dictionary, making sure it never exceeds a specified maximum limit!
defincrement_value_with_max_limit(d,key,inc,limit):"""
Increment the value of d[key] by inc, but do not let it exceed limit.
Args:
d (dict): Dictionary with integer values.
key: Key whose value you want to increment.
inc (int): The increment value.
limit (int): The maximum allowed value.
Returns:
None: The dictionary is modified in-place.
Example:
d = {'a': 5}
increment_value_with_max_limit(d, 'a', 10, 12)
# Now d['a'] == 12
"""ifkeyind:d[key]=min(d[key]+inc,limit)
✨ Step-by-Step Explanation
Check Key Exists:
Make sure the key is present in the dictionary.
Increment and Cap:
Add the inc value to the current value for the key.
Use min(new_value, limit) to cap the result at limit if it would go over.
Update In Place:
The original dictionary is modified directly. No return value necessary!
📝 Practice Questions
If d = {'x': 7}, what does increment_value_with_max_limit(d, 'x', 4, 10) do?
What happens for d = {'b': 2}, increment_value_with_max_limit(d, 'b', 5, 5)?
Try d = {'score': 20}, increment_value_with_max_limit(d, 'score', 3, 22)
✅ Solutions
The value becomes min(7+4, 10) = 10. So, d['x'] will be 10.
The value becomes min(2+5, 5) = 5. So, d['b'] will be 5.
The value becomes min(20+3, 22) = 22. So, d['score'] will be 22.
💡 Now you can safely increment dictionary values without ever exceeding the maximum you set!
