Examples of Set Operations and Counting Problems

Examples of Set Operations and Counting Problems

A well-defined collection of distinct objects called elements or members.

Learning Outcomes:

  1. Understand set notations.
  2. Solve counting problems using Venn diagrams.

Here is a detailed guide covering set notations and solving counting problems using Venn diagrams with 10 examples, including diagrams and emojis to enhance clarity.


1๏ธโƒฃ Understanding Set Notations

Basic Set Notations and Symbols:

  • Set: Denoted by curly braces ${}$. Example: $A = {1,2,3}$
  • Element of a Set: $x \in A$ means $x$ is in set $A$.
  • Not an Element: $x \notin A$ means $x$ is not in set $A$.
  • Subset: $A \subseteq B$ means every element of $A$ is in $B$.
  • Proper Subset: $A \subset B$ means $A$ is subset but not equal to $B$.
  • Empty Set: $\emptyset$, set with no elements.
  • Universal Set: $U$, all elements under consideration.
  • Union: $A \cup B = {x | x \in A \text{ or } x \in B}$
  • Intersection: $A \cap B = {x | x \in A \text{ and } x \in B}$
  • Set Difference: $A - B = {x | x \in A \text{ and } x \notin B}$
  • Complement: $A^c = U - A$

Visual Diagram of Set Operations:

Basic Set Notations

Basic Set Notations

๐Ÿ”ต โˆช, ๐Ÿ”ด โˆฉ, areas represent unions and intersections.


2๏ธโƒฃ Solve Counting Problems Using Venn Diagrams

Counting problems involving overlapping sets can be solved efficiently by Venn diagrams.


Example 1: Basic Two-Set Problem

  • 40 students study Math, 30 study English, and 10 study both.
  • How many students study at least one?
$$ |M \cup E| = |M| + |E| - |M \cap E| = 40 + 30 - 10 = 60 $$

Example 1 Venn


Example 2: Three-Set Problem

  • 50 students play football, 40 play basketball, 30 play volleyball, 20 play football & basketball,
  • 15 play basketball & volleyball, 10 play football & volleyball, 5 play all three.
  • Find how many play at least one sport.
$$ |F \cup B \cup V| = |F| + |B| + |V| - |F \cap B| - |B \cap V| - |F \cap V| + |F \cap B \cap V| $$

Calculate:

$$ 50 + 40 + 30 - 20 - 15 - 10 + 5 = 80 $$

Example 2 Venn


Example 3: Students in Subjects

  • 60 students: 35 study Physics, 30 Chemistry, 20 both.
  • How many study neither?

Assuming total = 60:

$$ |P \cup C| = 35 + 30 - 20 = 45 $$

Neither = $60 - 45 = 15$


Example 4: Overlapping Preferences

  • Out of 100 people, 70 like tea, 50 like coffee, 30 like both.
  • How many like either tea or coffee but not both?
$$ (70 - 30) + (50 - 30) = 60 $$

Example 5: Book Readers

  • 100 people reading books: 70 read fiction, 40 non-fiction, 25 both.
  • Find how many read only fiction.

Only fiction = $70 - 25 = 45$


Example 6: Survey with Three Choices

  • In a group, liked: A = 80, B = 65, C = 75, A&B = 45, B&C = 35, A&C = 30, All three = 25.
  • Find how many liked none if total is 150.

At least one:

$$ 80 + 65 + 75 - 45 - 35 - 30 + 25 = 135 $$

None = $150 - 135 = 15$


Example 7: Sports Participation

  • 70 students play Cricket, 60 Football, 50 Hockey, 30 Cricket & Football,
  • 20 Football & Hockey, 15 Cricket & Hockey, 5 all three.
  • How many play only one sport?

Calculate only one set:

$$ \begin{cases} C \text{ only} = 70 - 30 - 15 + 5 = 30 \\ F \text{ only} = 60 - 30 - 20 + 5 = 15 \\ H \text{ only} = 50 - 15 - 20 + 5 = 20 \\ \end{cases} $$

Example 8: Analyzing Survey Data

  • 120 people surveyed: 50 like apples, 70 like bananas, 30 like both.
  • How many like only one fruit?
$$ (50 - 30) + (70 - 30) = 60 $$

Example 9: Multi-Category Venn

  • In a town: 200 people use Internet, 150 use TV, 100 use Newspaper,
  • Internet & TV = 80, TV & Newspaper = 60, Internet & Newspaper = 40,
  • All three = 20, total population 300.
  • How many use none?

Calculate people using any:

$$ 200 + 150 + 100 - 80 - 60 - 40 + 20 = 290 $$

None = $300 - 290 = 10$


Example 10: Students with Multiple Skills

  • 45 students know Java, 30 know Python, 20 know both.
  • Total students = 60.
  • How many know neither?
$$ |J \cup P| = 45 + 30 - 20 = 55 $$

Neither = $60 - 55 = 5$


These examples utilize Venn diagrams and formulas to solve counting problems involving sets effectively.


Emojis summary:

  • ๐Ÿ”ท Set notation
  • ๐Ÿ”ต Circle for sets in diagrams
  • ๐Ÿงฎ Counting elements
  • ๐ŸŽฏ Intersection and union
  • โŒ Excluding elements

These illustrations and examples offer solid practice in set theory and counting with Venn diagrams.


Exercise Questions ๐Ÿง 

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1) In a class of 40 students, 20 took Mathematics, 18 took Statistics, 16 took English, 7 took Mathematics and Statistics, 7 took Mathematics and English, 9 took Statistics and English, and 3 took all three courses. How many students are not taking any of these courses?

Detailed Solution:

Let:

  • $ n = 40 $
  • $ |M| = 20,|S| = 18,|E| = 16 $
  • $ |M \cap S| = 7, |M \cap E| = 7, |S \cap E| = 9 $
  • $ |M \cap S \cap E| = 3 $

Using the three-set inclusion-exclusion principle:

$$ |M \cup S \cup E| = |M| + |S| + |E| - |M \cap S| - |S \cap E| - |M \cap E| + |M \cap S \cap E| $$$$ = 20 + 18 + 16 - 7 - 9 - 7 + 3 = 47 - 23 + 3 = 27 $$

So, number not taking any is:

$$ n - |M \cup S \cup E| = 40 - 27 = 13 $$

But let us carefully verify calculation:

$$ = 20 + 18 + 16 - 7 - 9 - 7 + 3 = 54 - 23 + 3 = 34 $$$$ = 54 - 23 = 31, 31+3=34 $$

So,

$$ 40 - 34 = 6 $$

Correct Answer: 6

2) In a survey, it is found that 30 people like apples, 45 people like oranges, and 20 people like both apples and oranges. How many people like only one fruit?

Detailed Solution:

People who like only apples: $ 30 - 20 = 10 $ People who like only oranges: $ 45 - 20 = 25 $ Total who like only one fruit: $ 10 + 25 = 35 $

Correct Answer: 35

3) In a class, 50 students play cricket, 35 play football, 14 play both, and 9 play neither. How many students are there in the class?

Detailed Solution:

Let $ n $ be the total number.

Using formula:

$$ n = (\text{Cricket}) + (\text{Football}) - (\text{Both}) + (\text{Neither}) $$$$ = 50 + 35 - 14 + 9 = 80 $$

Correct Answer: 80

4) A group of 25 people are planning to get togetherโ€ฆ9 suggested Goa, 8 suggested Bangkok, $ X $ suggested Pondicherry, and 3 did not suggest any place. Considering each person suggested only one place, what is the value of $ X $?

Detailed Solution:

Total suggesting places: $ 25 - 3 = 22 $ Thus,

$$ 9 (\text{Goa}) + 8 (\text{Bangkok}) + X = 22 $$$$ X = 22 - (9+8) = 5 $$

Correct Answer: 5

5) An advertising agency finds that, of its 200 clients who use Television or Radio or both, 150 use Television. How many use only Radio?

Detailed Solution:

Let number who use both be $ x $, $ T = 150 $, $ T \cup R = 200 $.

We do not have the count of clients who use both or who use Radio. Thus, we cannot uniquely determine the number who use only Radio.

Correct Answer: Data is insufficient

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