Functions
A well-defined collection of distinct objects called elements or members.
1️⃣ Define Function, Domain, Co-domain, and Range
- Function: A relation $f$ from set $A$ (domain) to set $B$ (co-domain) that assigns each element in $A$ exactly one element in $B$. Denoted as $f: A \to B$.
- Domain ($A$): The set of input values over which the function is defined. Example: $A = {1,2,3}$.
- Co-domain ($B$): The set where outputs of the function lie. Example: $B = {a,b,c,d}$.
- Range: The subset of the co-domain actually mapped by the function. For example, if $f(1) = a, f(2) = b, f(3) = a$, then range $= {a,b}$.
Diagram: Function Mapping
🎯 Each arrow shows the mapping from domain to co-domain. Each domain element maps to exactly one codomain element.
2️⃣ Identify Domain and Range of a Given Function
- Example: $f:\mathbb{R} \to \mathbb{R}$, defined by $f(x) = x^2$.
- Domain: All real numbers ($\mathbb{R}$).
- Range: Non-negative real numbers $[0, \infty)$, because squaring any real number can’t be negative.
Diagram of Domain to Range
🟢 All inputs from domain map to outputs in range.
3️⃣ Classify a Function: Injective, Surjective, Both or Neither
- Injective (One-to-One): Different inputs map to different outputs.
- Example: $f(x) = 2x$ over real numbers (distinct inputs produce distinct outputs).
- Surjective (Onto): Every element in the co-domain is mapped to by some input.
- Example: $f(x) = x^3$ over real numbers (every real number has a cube root).
- Bijective: Both injective and surjective.
- Neither: Does not satisfy injective or surjective properties.
Diagram Examples
🔄 Injection: no two arrows go to the same place. Finish of the co-domain: surjection. Both: bijection.
4️⃣ Define Bijection
- Bijection: A function that is both injective and surjective. It has an inverse function $f^{-1}$ that maps the co-domain back to domain one-to-one.
- Example: $f:\mathbb{R} \to \mathbb{R}$, $f(x) = x + 3$
- Inverse is $f^{-1}(y) = y - 3$.
- Properties: Bijections pair elements perfectly without overlaps or gaps.
Diagram of Bijection and Inverse
🎯 Each input maps uniquely to an output and vice versa.
Summary Emojis
- 🎯 Function mapping
- 🔢 Inputs and outputs
- 🔄 Injection, surjection visuals
- 🚀 Bijection and inverse
This detailed guide provides a clear understanding of functions and their classification, accompanied by rich visuals.
1. Define a function, domain, co-domain, and range of a function.
- Function: A relation from set $A$ (domain) to set $B$ (co-domain) where every element of $A$ maps to exactly one element of $B$. Notation: $f: A \to B$.
- Domain: The set of all possible inputs, $A$.
- Co-domain: The set in which outputs lie, $B$.
- Range: The set of all actual outputs $f(x)$ for $x \in A$, subset of $B$.
Example: $f(x) = x^2$, $A = \mathbb{R}$, $B = \mathbb{R}$, range = $[0, \infty)$.
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2. Identify the domain and range of a given function
Given $f(x) = x^2$:
- Domain = All real numbers $\mathbb{R}$.
- Range = All non-negative real numbers $[0, \infty)$ since squares are $\geq 0$.
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3. Classify a function as injective, surjective, both, or neither
- Injective (One-to-one): No two different inputs share the same output. Example: $f(x) = 2x$ over $\mathbb{R}$ (each input maps to distinct outputs).
- Surjective (Onto): Every element in co-domain is covered by some input. Example: $f(x) = x^3$ over $\mathbb{R}$.
- Bijective: Both injective and surjective; one-to-one and onto.
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4. Define bijection with examples
- Bijection: A function that is both injective and surjective. It has an inverse function.
Example: $f: \mathbb{R} \to \mathbb{R}, f(x) = x + 3$. Inverse is $f^{-1}(y) = y - 3$.
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Exercise Questions 🤯
2) Let $ f(x) = |x| + 5 $ and $ Dom(f) = {x \in \mathbb{R} \mid f(x) \in \mathbb{R}} $. Which of the following is(are) true?
Options:
- Domain of $ f(x) $ is $ \mathbb{R} $
- Range of $ f(x) $ is $ \mathbb{R} $
- Domain of $ f(x) $ is $[5, \infty)$
- Range of $ f(x) $ is $[5, \infty)$
Detailed Answer:
- For any $ x \in \mathbb{R} $, $ f(x) $ is defined (so domain is $ \mathbb{R} $)
- $ f(x) = |x| + 5 $. The smallest value is 5 (when $ x = 0 $); as $ x $ increases or decreases, value increases to infinity.
- So, the range is $[5, \infty)$.
Correct Options:
- Domain of $ f(x) $ is $ \mathbb{R} $
- Range of $ f(x) $ is $[5, \infty)$
3) Let $ f : \mathbb{R} \to \mathbb{R} $ and $ f(x) = |(x+4)(4x-10)| $. Which of the following is(are) true?
Options:
- $ f $ is an injective function
- $ f $ is a surjective function
- $ f $ is a bijective function
- None of these
Detailed Answer:
- Because of the absolute value, different $ x $ values can yield the same output. Hence, $ f $ is not injective.
- As $ x $ varies over $ \mathbb{R} $, $ f(x) $ returns values in $[0, \infty)$, not all real numbers, so not surjective onto $\mathbb{R}$.
- So, it is neither injective nor surjective.
Correct Answer: None of these
4) Which of the following statements is(are) false?
Options:
- Range of a function is a subset of co-domain
- A function is bijective if and only if it is both injective and surjective
- Every relation is a function
- Co-domain of a function is a subset of domain
Detailed Answer:
- Range of function is a subset of co-domain: True
- Function bijective iff injective and surjective: True
- Every relation is a function: False (a function is a special kind of relation; not all relations are functions)
- Co-domain is a subset of domain: False (Co-domain and domain are unrelated sets, other than mapping).
Correct Answers:
- Every relation is a function
- Co-domain of a function is a subset of domain
5) Let $x \in \mathbb{R}$ and $DOM(f) = {x \in \mathbb{R} \mid f(x) \in \mathbb{R}}$. Which of the following functions is(are) injective?
Options:
- $f(x) = \sqrt{10-x}$
- $f(x) = \frac{7x+6}{3x}$
- $f(x) = 2x+9$
- $f(x) = \frac{(5x+4)(2x-3)}{2}$
Detailed Answer:
- $f(x) = \sqrt{10-x}$: Not injective (not one-to-one, not defined for $ x > 10 $)
- $f(x) = \frac{7x+6}{3x}$: Not injective (not defined at $ x=0 $ and not one-to-one over all $ x $)
- $f(x) = 2x+9$: Injective (one-to-one linear function)
- $f(x) = \frac{(5x+4)(2x-3)}{2}$: Injective (quadratic in factorized form but for many quadratic forms, over $\mathbb{R}$, not always injective; but this function is strictly increasing or decreasing outside critical points; check derivative for monotonicity.)
But over $\mathbb{R}$, only linear function is always injective without ambiguity.
Correct Answer: $ f(x) = 2x+9 $
6) Suppose $ f : \mathbb{Z} \to \mathbb{Z} $ is a function defined by $ f(x) = ax + b $. For which of the following integer values of $ a $ and $ b $ is the given function bijective?
Options:
- $ a = 0, b = t; t \in \mathbb{Z} $
- $ a \in {-1, 1}, b = t; t \in \mathbb{Z} $
- $ b \in {-1, 1}, a = 0 $
- $ b = 0; a \in \mathbb{Z} $
Detailed Answer:
- $ a = 0 $: $ f(x) $ is constant — not bijective
- $ a = 1, b \in \mathbb{Z} $: $ f(x) = x+b $ is a bijection (inverse: $ x = y-b $)
- $ a = -1, b \in \mathbb{Z} $: $ f(x) = -x + b $, also a bijection (inverse: $ x = b-y $)
Correct Answer: $ a \in {-1, 1}, b = t; t \in \mathbb{Z} $