Algebra of polynomials - Multiplication
A well-defined collection of distinct objects called elements or members.
Learning Outcomes
Compute the product of two general polynomials using corresponding coefficients.
Exercise Questions 🤯
Good evening! Here in India on this Sunday, let’s work through these questions, which focus on the multiplication of polynomials and understanding the properties of the resulting product.
Core Concepts: Multiplication of Polynomials
The Process: To multiply two polynomials, you must multiply every term in the first polynomial by every term in the second polynomial. Afterwards, you combine any “like terms” (terms with the same power of x) to simplify.
Degree of the Product: The degree of the product of two non-zero polynomials is simply the sum of their individual degrees.
degree(p(x) * q(x)) = degree(p(x)) + degree(q(x))
Leading Coefficient of the Product: The leading coefficient of the product is the product of the leading coefficients of the original polynomials.
Slope of a Polynomial: The “slope” of a polynomial at any point is given by its derivative. For a term $ax^n$, its derivative is $(a \cdot n)x^{n-1}$.
Question 1: Product of a Polynomial and its Slope (from file image_d19339.png
)
The Question: If the polynomial $r(x)$ is the product of a degree two polynomial $p(x) = -8x^2 - 12x + 2$ and its slope then the coefficient of term with highest power is __________.
Core Concept: The term with the highest power in the product polynomial, $r(x)$, is the product of the highest power terms of the original polynomials.
Detailed Solution:
Identify the first polynomial, $p(x)$:
- $p(x) = -8x^2 - 12x + 2$.
- Its highest power term is $-8x^2$. Its degree is 2.
Find the slope of $p(x)$ by finding its derivative, $p’(x)$:
- The derivative of $-8x^2$ is $(2 \cdot -8)x^{2-1} = -16x$.
- The derivative of $-12x$ is $-12$.
- The derivative of $2$ is $0$.
- So, the slope is $p’(x) = -16x - 12$.
- Its highest power term is $-16x$. Its degree is 1.
Find the highest power term of the product, $r(x)$:
- $r(x) = p(x) \times p’(x)$.
- The highest power term of $r(x)$ is the product of the highest power terms of $p(x)$ and $p’(x)$.
- Highest Term = $(-8x^2) \times (-16x) = 128x^3$.
Identify the coefficient:
- The coefficient of the highest power term ($x^3$) is 128.
Final Answer: 128
Question 2: Product of Two Polynomials (from file image_d19339.png
)
The Question: The product of the polynomials $p(x) = 2x^2 + 2x + 2$ and $q(x) = x^2 - x - 1$ is __________.
Core Concept: Use the distributive property to multiply every term in $p(x)$ by every term in $q(x)$.
Detailed Solution:
Set up the multiplication: $(2x^2 + 2x + 2)(x^2 - x - 1)$
Distribute each term of the first polynomial:
- Multiply by $2x^2$: $2x^2(x^2 - x - 1) = 2x^4 - 2x^3 - 2x^2$
- Multiply by $2x$: $2x(x^2 - x - 1) = 2x^3 - 2x^2 - 2x$
- Multiply by $2$: $2(x^2 - x - 1) = 2x^2 - 2x - 2$
Add the results and combine like terms:
$$(2x^4 - 2x^3 - 2x^2) + (2x^3 - 2x^2 - 2x) + (2x^2 - 2x - 2)$$$$= 2x^4 + (-2x^3 + 2x^3) + (-2x^2 - 2x^2 + 2x^2) + (-2x - 2x) - 2$$$$= 2x^4 + 0x^3 - 2x^2 - 4x - 2$$
Final Answer: $2x^4 - 2x^2 - 4x - 2$
Question 3: Multiplication Formula in Summation Notation (from file image_d19281.png
)
The Question: Choose the correct option(s) with respect to the product of the polynomials $p(x) = \sum_{k=0}^{n} a_k x^k$ and $q(x) = \sum_{j=0}^{m} b_j x^j$.
Core Concept: The Cauchy Product for Polynomials
This formula looks complex, but it’s a formal way of saying what we do when we multiply. The coefficient of a term like $x^k$ in the final product is found by summing up all the products of coefficients ($a_j b_i$) where the powers add up to $k$ (i.e., $j+i=k$).
The formula is:
$$p(x) \times q(x) = \sum_{k=0}^{m+n} \left( \sum_{j=0}^{k} a_j b_{k-j} \right) x^k$$Detailed Solution:
- Degree of the Product: The highest power in the result will be $x^{m+n}$. So the outer sum must go from $k=0$ to $m+n$.
- Coefficient of $x^k$: As stated in the concept, the coefficient for any term $x^k$ is the sum of products of coefficients $a_j$ and $b_{k-j}$ for all possible $j$ from 0 to $k$. This is written as $\sum_{j=0}^{k} a_j b_{k-j}$.
- Putting it together: This gives the formula $p(x) \times q(x) = \sum_{k=0}^{m+n} \left( \sum_{j=0}^{k} a_j b_{k-j} \right) x^k$.
- Commutativity: Since polynomial multiplication is commutative, $p(x) \times q(x) = q(x) \times p(x)$. This means the same formula holds for the product in the reverse order.
Let’s check the options:
- The third option matches the formula for $p(x) \times q(x)$ exactly. TRUE.
- The fourth option gives the same correct formula for $q(x) \times p(x)$. TRUE.
- The other options incorrectly alter the exponents or the indices of the sums.
Final Answer: The correct options are:
- $p(x) \times q(x) = \sum_{k=0}^{m+n} \sum_{j=0}^{k} (a_j b_{k-j}) x^k$
- $q(x) \times p(x) = \sum_{k=0}^{m+n} \sum_{j=0}^{k} (a_j b_{k-j}) x^k$
Question 4: Analyzing the Product of Polynomials (from file image_d18f94.png
)
The Question: If $r(x) = p(x)q(x)$ where $p(x) = -2x^9 + 4x^5 + 2x^2 + 1$ and $q(x) = 8x^4 - 2x^2 + x$ then choose the correct option(s) from the following.
Detailed Solution:
Let’s evaluate each statement.
“Degree of $r(x)=13$ and coefficient of $x^{13}=-16$”
- Degree of $r(x) = \text{deg}(p) + \text{deg}(q) = 9 + 4 = 13$.
- The coefficient of the highest power term ($x^{13}$) is the product of the leading coefficients of $p(x)$ and $q(x)$.
- Coefficient = $(-2) \times (8) = -16$.
- This statement is TRUE.
“Degree of polynomial $r(x)=36$ and it has 0 coefficient.”
- FALSE. The degree is 13, not 36 ($9 \times 4$).
“Coefficient of $x^2$ in $r(x)$ and $q(x)$ is -2”
- In $q(x) = 8x^4 - 2x^2 + x$, the coefficient of $x^2$ is indeed -2.
- To get the $x^2$ term in $r(x)$, we find all pairs of terms from $p(x)$ and $q(x)$ that multiply to give a power of 2:
- $(2x^2 \text{ from } p) \times (\text{constant term from } q) = 2x^2 \times 0 = 0$
- $(\text{constant term from } p) \times (-2x^2 \text{ from } q) = 1 \times (-2x^2) = -2x^2$
- The total coefficient of $x^2$ in $r(x)$ is $0 + (-2) = -2$.
- The statement is TRUE.
“Coefficient of $x^8$ in $r(x)$ is 0”
- To get an $x^8$ term, we need terms with powers that sum to 8. Let’s check the possibilities:
- $p(x)$ has powers 9, 5, 2, 0.
- $q(x)$ has powers 4, 2, 1.
- Can we combine any pair to get 8? (9+?) no, (5+?) no, (2+?) no, (0+?) no.
- Since there is no way to form an $x^8$ term, its coefficient must be 0. This statement is TRUE.
- To get an $x^8$ term, we need terms with powers that sum to 8. Let’s check the possibilities:
“Coefficient of $x^9$ in $r(x)$ and $p(x)$ is 32 and -2 respectively”
- The coefficient of $x^9$ in $p(x)$ is clearly -2.
- To get the $x^9$ term in $r(x)$, we find all pairs with powers that sum to 9:
- $(-2x^9 \text{ from } p) \times (\text{constant from } q) = -2x^9 \times 0 = 0$
- $(4x^5 \text{ from } p) \times (8x^4 \text{ from } q) = 32x^9$
- The total coefficient of $x^9$ in $r(x)$ is $0 + 32 = 32$.
- The statement is TRUE.
Final Answer: The correct statements are:
- Degree of $r(x) = 13$ and coefficient of $x^{13} = -16$
- Coefficient of $x^2$ in $r(x)$ and $q(x)$ is -2
- Coefficient of $x^8$ in $r(x)$ is 0
- Coefficient of $x^9$ in $r(x)$ and $p(x)$ is 32 and -2 respectively