Interest

This summary breaks down the key concepts from the provided PDF on Interest for government exam preparation, with clear explanations, formulas, examples, cheat sheets, and practice questions.


Key Definitions

  • Interest: The extra amount paid for borrowing money or received for lending money.
  • Principal (P): The original amount borrowed or lent.
  • Amount (A): The total sum after adding interest to the principal ($A = P + \text{Interest}$).
  • Rate of Interest (r): The percentage charged or earned on the principal per year.
  • Time (t): The period for which money is borrowed or deposited (usually in years).

Types of Interest

Simple Interest (SI)

  • Definition: Interest calculated only on the principal for every year.
  • Formula:
$$ SI = \frac{P \times r \times t}{100} $$

Where: - $P$ = Principal - $r$ = Rate per annum - $t$ = Time in years

Cheatsheet:

  • If time is in months: $ t = \frac{months}{12} $
  • If time is in days: $ t = \frac{days}{365} $

Example:

Q: Rs.1080 invested for 3 months gave an interest of Rs.27. What is the annual rate?

Solution: $ t = \frac{3}{12} = 0.25 $ years $ 27 = \frac{1080 \times r \times 0.25}{100} $ $ r = 10% $


Compound Interest (CI)

  • Definition: Interest calculated on the principal plus accumulated interest.
  • Formula for Amount (A):
$$ A = P \left(1 + \frac{r}{100}\right)^t $$
  • Compound Interest:
$$ CI = A - P $$

Special Cases:

  • Compounded Half-Yearly: Use $ r/2 $ and $ 2t $
$$ A = P \left(1 + \frac{r}{2 \times 100}\right)^{2t} $$
  • Compounded Quarterly: Use $ r/4 $ and $ 4t $
$$ A = P \left(1 + \frac{r}{4 \times 100}\right)^{4t} $$
  • Variable Rates: For different rates each year:
$$ A = P \left(1 + \frac{r_1}{100}\right)\left(1 + \frac{r_2}{100}\right)\left(1 + \frac{r_3}{100}\right)... $$

Example 1:

Q: Find CI on Rs.50,000 at 12% per annum for 1 year, compounded half-yearly.

Solution: $ r = 6% $, $ t = 2 $ $ A = 50,000 \left(1 + \frac{6}{100}\right)^2 = 50,000 \times 1.1236 = 56,180 $ $ CI = 56,180 - 50,000 = 6,180 $

Example 2:

Q: Rs.25,000 at CI for 3 years at rates 4%, 8%, 10% for each year.

Solution: $ A = 25,000 \times 1.04 \times 1.08 \times 1.10 = 30,888 $


Comparison Table: Simple vs. Compound Interest

FeatureSimple Interest (SI)Compound Interest (CI)
Formula$ \frac{P \times r \times t}{100} $$ P \left(1 + \frac{r}{100}\right)^t - P $
Interest onPrincipal onlyPrincipal + Accumulated Interest
GrowthLinearExponential

Shortcuts and Effective Rate

  • Effective Rate for 2 years at r%: $ Effective Rate = r + r + \frac{r^2}{100} $
  • Difference between CI and SI for 2 years: $ D = \frac{P \times r^2}{100^2} $

Example:

Q: Difference between CI and SI on Rs.3,000 at 10% for 2 years?

Solution: $ D = \frac{3,000 \times 10^2}{100^2} = 30 $


Tree Method for CI

  • Assume a simple principal (like Rs.100 or Rs.1,000) to make calculations easier.
  • Calculate interest for each year, including interest on previous interest.

Example:

Q: CI for Rs.10,000 at 10% for 3 years.

Year 1: $ 1,000 $ Year 2: $ 1,100 $ (1,000 + 100) Year 3: $ 1,210 $ (1,000 + 100 + 100 + 10) Total: $ 1,000 + 1,100 + 1,210 = 3,310 $


Installments

  • Used for calculating the price when paying in equal installments with interest.

Example:

Q: Oven bought in 4 installments of Rs.2,500 at 10% SI. What is the price?

Solution: Assume installment is Rs.100, total payments = 460 Actual price = $ 2,500 \times \frac{460}{100} = 11,500 $


Practice Questions

  1. Calculate the SI on Rs.2,000 at 8% for 18 months.
  2. Find the CI on Rs.5,000 at 10% for 2 years, compounded annually.
  3. What is the difference between SI and CI on Rs.1,500 at 12% for 2 years?
  4. If Rs.1,200 becomes Rs.1,512 in 2 years at CI, what is the rate?
  5. A sum is invested at 5% SI and earns Rs.200 in 4 years. Find the principal.

Cheatsheet Summary

  • SI Formula: $ SI = \frac{P \times r \times t}{100} $
  • CI Formula: $ CI = P \left(1 + \frac{r}{100}\right)^t - P $
  • Effective Rate (2 years): $ r + r + \frac{r^2}{100} $
  • Time Conversion: Months $ \rightarrow $ Years: $ \frac{months}{12} $, Days $ \rightarrow $ Years: $ \frac{days}{365} $
  • Difference (CI - SI, 2 years): $ \frac{P \times r^2}{100^2} $

This structured approach, with formulas, worked examples, and practice, should make mastering interest calculations for exams much easier.

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