One to One Functions | Definition & Tests
Absolutely! Let’s dive into one-to-one functions, making it easy to understand with definitions, tests, examples, and practice questions. ๐ฏ
What is a One-to-One Function? ๐ค
A one-to-one function, also known as an injective function, is a special type of mathematical relationship where each unique input from the domain maps to a unique output in the co-domain. Think of it like this:
- Imagine a class where every student has a unique student ID. No two different students can have the same ID. That’s a one-to-one relationship! โ ๐งโ๐๐
- If, however, two different students could have the same ID (e.g., student 1 and student 2 both have ID 123), then it’s not one-to-one. ๐ โโ๏ธ
More formally, a function f: A โ B
is considered one-to-one if for any two elements xโ
and xโ
in the domain A
:
- If
f(xโ) = f(xโ)
, then it must implyxโ = xโ
. (Meaning, if the outputs are the same, the inputs had to be the same). - Alternatively, if
xโ โ xโ
, then it must implyf(xโ) โ f(xโ)
. (Meaning, different inputs always lead to different outputs).
How to Test if a Function is One-to-One ๐๐ง
There are two primary methods to check if a function is one-to-one:
The Horizontal Line Test (HLT) ๐ This is a graphical test.
- How it works: If you can draw any horizontal line that intersects the graph of the function at more than one point, then the function is not one-to-one. โ
- Conversely, if every horizontal line you draw intersects the graph at at most one point (meaning it intersects once or not at all), then the function is one-to-one. โ
Example: The graph of
f(x) = |x|
is a V-shape. If you draw a horizontal line aty=2
, it intersects the graph atx=2
andx=-2
. Since it intersects at more than one point,f(x) = |x|
is not one-to-one.The Algebraic Test This method uses the formal definition.
- How it works:
- Start by assuming
f(xโ) = f(xโ)
. - Use algebraic manipulation to show that this assumption forces
xโ
to be equal toxโ
. - If you can consistently arrive at
xโ = xโ
, the function is one-to-one. If you find cases wherexโ โ xโ
butf(xโ) = f(xโ)
(like forf(x) = xยฒ
, wheref(2)=4
andf(-2)=4
), then it’s not one-to-one.
- Start by assuming
- How it works:
Key Theorems about One-to-One Functions ๐
Theorem on Monotonicity: If a function is strictly increasing or strictly decreasing throughout its domain, then the function is one-to-one.
- Explanation: If a function is always going up (increasing) or always going down (decreasing), it will never return to the same y-value for different x-values. Think of a staircase: if you only ever go up, you won’t land on the same step twice unless you haven’t moved. โฌ๏ธโฌ๏ธ
- Example: Exponential functions like
f(x) = a^x
(wherea > 1
) are strictly increasing, andf(x) = a^x
(where0 < a < 1
) are strictly decreasing. Therefore, exponential functions are one-to-one functions. Similarly, logarithmic functions are also one-to-one. Linear functions likef(x) = ax + b
(wherea โ 0
) are also either strictly increasing or strictly decreasing, making them one-to-one.
Theorem on Inverse Functions: A function
f
is one-to-one if and only if its inverse functionfโปยน
exists.- Explanation: For an inverse function to exist, it must be possible to “reverse” the mapping uniquely. If two different inputs
xโ
andxโ
map to the same outputy
, then when you try to go back fromy
, you wouldn’t know whether to go toxโ
orxโ
. A one-to-one function guarantees this unique reverse mapping. โฉ๏ธ
- Explanation: For an inverse function to exist, it must be possible to “reverse” the mapping uniquely. If two different inputs
Examples to Enhance Understanding ๐ก
Let’s look at more examples and apply our tests:
Linear Function:
f(x) = 2x + 3
- Algebraic Test: Assume
f(xโ) = f(xโ)
.2xโ + 3 = 2xโ + 3
2xโ = 2xโ
xโ = xโ
- Conclusion: Since
f(xโ) = f(xโ)
impliesxโ = xโ
,f(x) = 2x + 3
is a one-to-one function โ . (It’s also strictly increasing, confirming this by the monotonicity theorem).
- Algebraic Test: Assume
Quadratic Function:
f(x) = xยฒ
- Algebraic Test: Assume
f(xโ) = f(xโ)
.xโยฒ = xโยฒ
- This means
xโ = xโ
orxโ = -xโ
. - Since
xโ
does not have to be equal toxโ
(e.g., ifxโ = 2
, thenxโ
could be2
or-2
, andf(2) = f(-2) = 4
), the conditionxโ = xโ
is not forced.
- Horizontal Line Test: The graph of
f(x) = xยฒ
is a parabola opening upwards. A horizontal line drawn above the x-axis will intersect the parabola at two points. - Conclusion:
f(x) = xยฒ
is not a one-to-one function ๐ซ.
- Algebraic Test: Assume
Cubic Function:
f(x) = xยณ
- Algebraic Test: Assume
f(xโ) = f(xโ)
.xโยณ = xโยณ
- Taking the cube root of both sides,
xโ = xโ
.
- Horizontal Line Test: The graph of
f(x) = xยณ
always passes the horizontal line test (each horizontal line intersects at most once). - Conclusion:
f(x) = xยณ
is a one-to-one function โ . (It’s also strictly increasing, as seen in the source).
- Algebraic Test: Assume
Practice Questions with Solutions ๐
Question 1: Is the function f(x) = x + 5
a one-to-one function? Justify your answer using the algebraic test. ๐ค
Solution:
Yes, f(x) = x + 5
is a one-to-one function. โ
- Justification (Algebraic Test):
- Assume
f(xโ) = f(xโ)
. - Substitute the function definition:
xโ + 5 = xโ + 5
. - Subtract
5
from both sides:xโ = xโ
. - Since the assumption
f(xโ) = f(xโ)
directly impliesxโ = xโ
, the function satisfies the definition of a one-to-one function.
- Assume
Question 2: Consider the function f(x) = (1/2)^x
. Is this function one-to-one? Justify your answer using a relevant theorem. ๐ง
Solution:
Yes, the function f(x) = (1/2)^x
is a one-to-one function. โ
- Justification (Monotonicity Theorem):
- The function
f(x) = (1/2)^x
is an exponential function with a basea = 1/2
. - The sources state that when the base
a
is between0
and1
(i.e.,0 < a < 1
), an exponential function is a decreasing function. Specifically, ifxโ < xโ
, thena^xโ > a^xโ
. - A key theorem states that if a function is an increasing or decreasing function, then it is one-to-one.
- Therefore, since
f(x) = (1/2)^x
is a strictly decreasing function, it is one-to-one. Graphically, it would pass the Horizontal Line Test.
- The function
Question 3: Is the relation represented by the graph of a circle, say xยฒ + yยฒ = rยฒ
, a one-to-one function? Explain why or why not, referring to one of the graphical tests. โญ
Solution:
No, the graph of a circle xยฒ + yยฒ = rยฒ
does not represent a one-to-one function, because a circle is not even a function to begin with. ๐ซ
- Justification (Vertical Line Test):
- A preliminary test for any relation to be a function is the Vertical Line Test (VLT). If a vertical line intersects the graph at more than one point, the relation is not a function.
- If you draw a vertical line through a circle (except at its extreme left and right points), it will intersect the circle at two distinct points. This means for a single
x
input, there are twoy
outputs. - Since the circle fails the Vertical Line Test, it is not a function. Consequently, it cannot be a one-to-one function.
This concludes the explanation of one-to-one functions! I hope the emojis and clear steps made it easier to grasp! ๐