Week 7 - Sequence and Limits
Graded Assignment
1. Multiple Choice/Statement Analysis
Statements about sequences:
- Statement: If ${a_n}$ and ${b_n}$ are two sequences of real numbers, then ${a_n + b_n}$ is a convergent sequence.
- Counterexample: Let $a_n = 1$ for all $n$, $b_n = -1$ for all $n$. Both converge, but $a_n + b_n = 0$ for all $n$, which is convergent. However, the PDF says “option 1 is not correct,” which may refer to a different statement or a misinterpretation. The given explanation is not clear, but the PDF concludes: “Hence option 1 is not correct.”
- Statement: If ${a_n}$ is an increasing sequence, then ${(-1)^n a_n}$ is a decreasing sequence.
- Counterexample: $a_n = n$ for all $n$. Then ${(-1)^n a_n}$ is not decreasing.
- Solution: Hence option 2 is not correct.
- Statement: If ${a_n} \to a$, ${b_n} \to b$, and both $a, b$ are non-zero, then ${a_n b_n} \to ab$ must be non-zero.
- Solution: This is correct.
- Conclusion: Option 3 is correct.
- Statement: If ${a_n} \to a$ and ${b_n} \to a$, then ${a_n - b_n} \to 0$.
- Solution: This is correct.
- Conclusion: Option 4 is correct.
- Statement: If a sequence is divergent, then any subsequence is also divergent.
- Counterexample: Let $a_n = n$ if $n$ is odd, $a_n = 1$ if $n$ is even. ${a_n}$ is divergent, but ${a_{2n}}$ is constant and hence convergent.
- Conclusion: Option 5 is not correct.
2. Function Type Matching
Match the following functions to their types:
- i) $f(x) = 3 \ln x - 2$
- Type: Logarithmic function (d)
- ii) $f(x) = 10 - 4x$
- Type: Linear function (c)
- iii) $f(x) = 2^x + 7$
- Type: Exponential function (a)
- iv) $f(x) = x^2 - 4x + 4$
- Type: Quadratic function (b)
3. Limit and Function Behavior
Given a graph and options:
- Option 2: $\lim_{x \to 0^+} f(x) = 0 = \lim_{x \to 0^-} f(x)$. Hence option 2 is correct.
- Option 5: At $x = \pi$ and $x = -\pi$ there are no sharp corners at the given curve. So, option 5 is correct.
- Interval $[-0.5\pi, 0.5\pi]$: The function is oscillatory (neither monotonically increasing nor monotonically decreasing).
4. Limit Calculations
- a) $\lim_{x \to 0} \frac{\log(1+x)}{\sin x} = 1$
- b) $\lim_{x \to 0} \frac{\sin 5x}{x} = 5$
- c) $\lim_{x \to 0} \frac{e^{x/2} - 1}{\sin 2x} = \frac{1}{4}$
5. Function Comparison
Given $f(x) > g(x)$ for all $x \ge x_0$ and $f(x) \le g(x)$ for $x \le x_0$:
- Option 2: $f(x)$ and $g(x)$ will never intersect for $x > x_0$ is incorrect, since $f(x_0) = g(x_0)$. Solution: Option 2 is incorrect.
6. Sequence Limit
Given:
$$ a_n = \frac{12n^2}{3n+5} - \frac{4n^2 + 7}{n+3} $$Simplify and find the limit as $n \to \infty$:
$$ a_n = \frac{16n^2 - 21n - 35}{3n^2 + 14n + 15} \implies \lim_{n \to \infty} a_n = \frac{16}{3} $$7. Function Limit and Monotonicity
Given:
$$ R(w) = \frac{50e^w}{10 + e^w} $$- Monotonicity: $R(w)$ is increasing.
- Limit as $w \to \infty$: $R(w) \to 50$
- Minimum $r \in \mathbb{Z}$ such that $R(w) < r$ for all $w$: $r = 50$
8. Advanced Limit Calculation
Given:
$$ \lim_{n \to \infty} e \sqrt[n]{n!} \left[ \log(1 + \frac{6}{n}) - \frac{e^{1/n} - 1}{\sqrt[n]{(2\pi n)}} \right] = 5 $$9. Curve Analysis
Both curve 1 and curve 2 have sharp corners at the origin (0,0). Hence, at the origin these two curves do not have tangents at the origin.
10. Sequence Sum and Limit
Given:
$$ a_n = \frac{9 + 15 + 21 + \dots + 3(2n-1)}{n^2} $$Simplify and find the limit as $n \to \infty$:
$$ a_n = \frac{3(n^2 - 1)}{n^2} = 3\left(1 - \frac{1}{n^2}\right) \implies \lim_{n \to \infty} a_n = 3 $$11. Limit Involving Floor Function
Given:
$$ 5 \lim_{x \to 3^+} [x] - 3 \lim_{x \to 1^-} [x] $$Solution:
$$ = 5 \times 3 - 3 \times 0 = 15 $$12–14. Algorithm Error Estimation
12. Error in estimation by Algorithm 1:
$$ a_n = \frac{n^2 + 5n}{6n^2 + 1}, \quad \lim_{n \to \infty} a_n = \frac{1}{6} \approx 0.166 $$Error in estimation by Algorithm 2:
$$ b_n = \frac{1}{8} + \frac{(-1)^n}{n}, \quad \lim_{n \to \infty} b_n = \frac{1}{8} = 0.125 $$Error in estimation by Algorithm 3:
$$ c_n = \frac{e^n + 4}{7e^n}, \quad \lim_{n \to \infty} c_n = \frac{1}{7} \approx 0.143 $$Conclusion:
- Maximum error: Algorithm 1
- Minimum error: Algorithm 2
13. Error in estimation by new algorithm:
$$ \lim (a_n - b_n) = \frac{1}{6} - \frac{1}{8} = \frac{1}{24} $$The error in estimation using the new algorithm is less than the error in estimation using any of the Algorithm 1, Algorithm 2 and Algorithm 3.
14. Limit calculation:
$$ c_n' = n e^{\frac{1}{8n}} - n $$$$ \lim_{n \to \infty} c_n' = \frac{1}{8} = 0.125 $$This covers all questions and solutions from the PDF1.
Week-7-Sequence-and-Limits.pdf ↩︎