Week 7 - Sequence and Limits

Week 7 - Sequence and Limits


Graded Assignment

1. Multiple Choice/Statement Analysis

Statements about sequences:

  1. Statement: If ${a_n}$ and ${b_n}$ are two sequences of real numbers, then ${a_n + b_n}$ is a convergent sequence.
    • Counterexample: Let $a_n = 1$ for all $n$, $b_n = -1$ for all $n$. Both converge, but $a_n + b_n = 0$ for all $n$, which is convergent. However, the PDF says “option 1 is not correct,” which may refer to a different statement or a misinterpretation. The given explanation is not clear, but the PDF concludes: “Hence option 1 is not correct.”
  2. Statement: If ${a_n}$ is an increasing sequence, then ${(-1)^n a_n}$ is a decreasing sequence.
    • Counterexample: $a_n = n$ for all $n$. Then ${(-1)^n a_n}$ is not decreasing.
    • Solution: Hence option 2 is not correct.
  3. Statement: If ${a_n} \to a$, ${b_n} \to b$, and both $a, b$ are non-zero, then ${a_n b_n} \to ab$ must be non-zero.
    • Solution: This is correct.
    • Conclusion: Option 3 is correct.
  4. Statement: If ${a_n} \to a$ and ${b_n} \to a$, then ${a_n - b_n} \to 0$.
    • Solution: This is correct.
    • Conclusion: Option 4 is correct.
  5. Statement: If a sequence is divergent, then any subsequence is also divergent.
    • Counterexample: Let $a_n = n$ if $n$ is odd, $a_n = 1$ if $n$ is even. ${a_n}$ is divergent, but ${a_{2n}}$ is constant and hence convergent.
    • Conclusion: Option 5 is not correct.

2. Function Type Matching

Match the following functions to their types:

  • i) $f(x) = 3 \ln x - 2$
    • Type: Logarithmic function (d)
  • ii) $f(x) = 10 - 4x$
    • Type: Linear function (c)
  • iii) $f(x) = 2^x + 7$
    • Type: Exponential function (a)
  • iv) $f(x) = x^2 - 4x + 4$
    • Type: Quadratic function (b)

3. Limit and Function Behavior

Given a graph and options:

  • Option 2: $\lim_{x \to 0^+} f(x) = 0 = \lim_{x \to 0^-} f(x)$. Hence option 2 is correct.
  • Option 5: At $x = \pi$ and $x = -\pi$ there are no sharp corners at the given curve. So, option 5 is correct.
  • Interval $[-0.5\pi, 0.5\pi]$: The function is oscillatory (neither monotonically increasing nor monotonically decreasing).

4. Limit Calculations

  • a) $\lim_{x \to 0} \frac{\log(1+x)}{\sin x} = 1$
  • b) $\lim_{x \to 0} \frac{\sin 5x}{x} = 5$
  • c) $\lim_{x \to 0} \frac{e^{x/2} - 1}{\sin 2x} = \frac{1}{4}$

5. Function Comparison

Given $f(x) > g(x)$ for all $x \ge x_0$ and $f(x) \le g(x)$ for $x \le x_0$:

  • Option 2: $f(x)$ and $g(x)$ will never intersect for $x > x_0$ is incorrect, since $f(x_0) = g(x_0)$. Solution: Option 2 is incorrect.

6. Sequence Limit

Given:

$$ a_n = \frac{12n^2}{3n+5} - \frac{4n^2 + 7}{n+3} $$

Simplify and find the limit as $n \to \infty$:

$$ a_n = \frac{16n^2 - 21n - 35}{3n^2 + 14n + 15} \implies \lim_{n \to \infty} a_n = \frac{16}{3} $$

7. Function Limit and Monotonicity

Given:

$$ R(w) = \frac{50e^w}{10 + e^w} $$
  • Monotonicity: $R(w)$ is increasing.
  • Limit as $w \to \infty$: $R(w) \to 50$
  • Minimum $r \in \mathbb{Z}$ such that $R(w) < r$ for all $w$: $r = 50$

8. Advanced Limit Calculation

Given:

$$ \lim_{n \to \infty} e \sqrt[n]{n!} \left[ \log(1 + \frac{6}{n}) - \frac{e^{1/n} - 1}{\sqrt[n]{(2\pi n)}} \right] = 5 $$

9. Curve Analysis

Both curve 1 and curve 2 have sharp corners at the origin (0,0). Hence, at the origin these two curves do not have tangents at the origin.


10. Sequence Sum and Limit

Given:

$$ a_n = \frac{9 + 15 + 21 + \dots + 3(2n-1)}{n^2} $$

Simplify and find the limit as $n \to \infty$:

$$ a_n = \frac{3(n^2 - 1)}{n^2} = 3\left(1 - \frac{1}{n^2}\right) \implies \lim_{n \to \infty} a_n = 3 $$

11. Limit Involving Floor Function

Given:

$$ 5 \lim_{x \to 3^+} [x] - 3 \lim_{x \to 1^-} [x] $$

Solution:

$$ = 5 \times 3 - 3 \times 0 = 15 $$

12–14. Algorithm Error Estimation

12. Error in estimation by Algorithm 1:

$$ a_n = \frac{n^2 + 5n}{6n^2 + 1}, \quad \lim_{n \to \infty} a_n = \frac{1}{6} \approx 0.166 $$

Error in estimation by Algorithm 2:

$$ b_n = \frac{1}{8} + \frac{(-1)^n}{n}, \quad \lim_{n \to \infty} b_n = \frac{1}{8} = 0.125 $$

Error in estimation by Algorithm 3:

$$ c_n = \frac{e^n + 4}{7e^n}, \quad \lim_{n \to \infty} c_n = \frac{1}{7} \approx 0.143 $$

Conclusion:

  • Maximum error: Algorithm 1
  • Minimum error: Algorithm 2

13. Error in estimation by new algorithm:

$$ \lim (a_n - b_n) = \frac{1}{6} - \frac{1}{8} = \frac{1}{24} $$

The error in estimation using the new algorithm is less than the error in estimation using any of the Algorithm 1, Algorithm 2 and Algorithm 3.

14. Limit calculation:

$$ c_n' = n e^{\frac{1}{8n}} - n $$$$ \lim_{n \to \infty} c_n' = \frac{1}{8} = 0.125 $$

This covers all questions and solutions from the PDF1.


  1. Week-7-Sequence-and-Limits.pdf ↩︎